Given an array of integers, find the largest difference between two elements such that the element of lesser value must come before the greater element

var array = [7, 8, 4, 9, 9, 15, 3, 1, 10];
// [7, 8, 4, 9, 9, 15, 3, 1, 10] would return `11` based on the difference between `4` and `15`
// Notice: It is not `14` from the difference between `15` and `1` because 15 comes before 1.

findLargestDifference(array);

function findLargestDifference(array) {
  // If there is only one element, there is no difference
  if (array.length <= 1) return -1;

  // currentMin will keep track of the current lowest
  var currentMin = array[0];
  var currentMaxDifference = 0;

  // We will iterate through the array and keep track of the current max difference
  // If we find a greater max difference, we will set the current max difference to that variable
  // Keep track of the current min as we iterate through the array, since we know the greatest
  // difference is yield from `largest value in future` - `smallest value before it`

  for (var i = 1; i < array.length; i++) {
    if (array[i] > currentMin && (array[i] - currentMin > currentMaxDifference)) {
      currentMaxDifference = array[i] - currentMin;
    } else if (array[i] <= currentMin) {
      currentMin = array[i];
    }
  }

  // If negative or 0, there is no largest difference
  if (currentMaxDifference <= 0) return -1;

  return currentMaxDifference;
}