This Java program is to check whether graph is Biconnected. In graph theory, a biconnected graph is a connected and “nonseparable” graph, meaning that if any vertex were to be removed, the graph will remain connected. Therefore a biconnected graph has no articulation vertices.
Here is the source code of the Java program to check whether graph is biconnected. The Java program is successfully compiled and run on a Linux system. The program output is also shown below.
import java.util.HashSet; import java.util.InputMismatchException; import java.util.LinkedList; import java.util.Queue; import java.util.Scanner; import java.util.Set; import java.util.Stack; public class BiconnectedGraph { private Queue<Integer> queue; private Stack<Integer> stack; private int numberOfNodes; private Set<Integer> articulationPoints; private int[] parent; private int[] visited; private int[][] adjacencyMatrix; public BiconnectedGraph(int numberOfNodes) { queue = new LinkedList<Integer>(); this.numberOfNodes = numberOfNodes; this.stack = new Stack<Integer>(); this.articulationPoints = new HashSet<Integer>(); this.parent = new int[numberOfNodes + 1]; this.visited = new int[numberOfNodes + 1]; this.adjacencyMatrix = new int[numberOfNodes + 1][numberOfNodes + 1]; } private boolean bfs(int adjacency_matrix[][], int source) { boolean connected = true; int number_of_nodes = adjacency_matrix.length - 1; int[] visited = new int[number_of_nodes + 1]; int i, element; visited = 1; queue.add(source); while (!queue.isEmpty()) { element = queue.remove(); i = element; while (i <= number_of_nodes) { if (adjacency_matrix[element][i] == 1 && visited[i] == 0) { queue.add(i); visited[i] = 1; } i++; } } for (int vertex = 1; vertex <= number_of_nodes; vertex++) { if (visited[vertex] == 1) { continue; }else { connected = false; break; } } return connected; } private int numberOfArticulationPoint(int adjacencyMatrix[][], int source) { int children = 0; int element, destination; stack.push(source); visited = 1; for (int sourceVertex = 1; sourceVertex <= numberOfNodes; sourceVertex++) { for (int destinationVertex = 1; destinationVertex <= numberOfNodes; destinationVertex++) { this.adjacencyMatrix[sourceVertex][destinationVertex] = adjacencyMatrix[sourceVertex][destinationVertex]; } } while (!stack.isEmpty()) { element = stack.peek(); destination = element; while (destination <= numberOfNodes) { if (this.adjacencyMatrix[element][destination] == 1 && visited[destination] == 0) { stack.push(destination); visited[destination] = 1; parent[destination] = element; if (element == source) { children++; } if (!isLeaf(this.adjacencyMatrix, destination)) { if (children > 1) { articulationPoints.add(source); } if(isArticulationPoint(this.adjacencyMatrix, destination)) { articulationPoints.add(destination); } } element = destination; destination = 1; continue; } destination++; } stack.pop(); } return articulationPoints.size(); } public boolean isArticulationPoint(int adjacencyMatrix[][], int root) { int explored[] = new int[numberOfNodes + 1]; Stack<Integer> stack = new Stack<Integer>(); stack.push(root); int element = 0,destination = 0; while(!stack.isEmpty()) { element = stack.peek(); destination = 1; while (destination <= numberOfNodes) { if ( element != root) { if (adjacencyMatrix[element][destination] == 1 && visited[destination] == 1) { if (this.stack.contains(destination)) { if (destination <= parent[root]) { return false; } return true; } } } if ((adjacencyMatrix[element][destination] == 1 && explored[destination] == 0 ) && visited[destination] == 0) { stack.push(destination); explored[destination] = 1; adjacencyMatrix[destination][element] = 0; element = destination; destination = 1; continue; } destination++; } stack.pop(); } return true; } private boolean isLeaf(int adjacencyMatrix[][], int node) { boolean isLeaf = true; for (int vertex = 1; vertex <= numberOfNodes; vertex++) { if (adjacencyMatrix[node][vertex] == 1 && visited[vertex] == 1) { isLeaf = true; }else if (adjacencyMatrix[node][vertex] == 1 && visited[vertex] == 0) { isLeaf = false; break; } } return isLeaf; } public boolean isBiconnected(int adjacencyMatrix[][], int source) { boolean biconnected = false; if (bfs(adjacencyMatrix, source) && numberOfArticulationPoint(adjacencyMatrix, source) == 0) { biconnected = true; } return biconnected; } public static void main(String... arg) { int number_of_nodes, source; Scanner scanner = null; try { System.out.println("Enter the number of nodes in the graph"); scanner = new Scanner(System.in); number_of_nodes = scanner.nextInt(); int adjacency_matrix[][] = new int[number_of_nodes + 1][number_of_nodes + 1]; System.out.println("Enter the adjacency matrix"); for (int i = 1; i <= number_of_nodes; i++) for (int j = 1; j <= number_of_nodes; j++) adjacency_matrix[i][j] = scanner.nextInt(); System.out.println("Enter the source for the graph"); source = scanner.nextInt(); BiconnectedGraph biconnectedGraph = new BiconnectedGraph(number_of_nodes); if (biconnectedGraph.isBiconnected(adjacency_matrix, source)) { System.out.println("The Given Graph is BiConnected"); }else { System.out.println("The Given Graph is Not BiConnected"); } } catch (InputMismatchException inputMismatch) { System.out.println("Wrong Input format"); } scanner.close(); } }
$javac BiConnectedGraph.java $java BiConnectedGraph Enter the number of nodes in the graph 5 Enter the adjacency matrix 0 1 1 1 0 1 0 1 0 0 1 1 0 0 1 1 0 0 0 1 0 0 1 1 0 Enter the source for the graph 1 The Given Graph is BiConnected
Related posts:
Guide to Java 8’s Collectors
Getting Started with GraphQL and Spring Boot
Java Program to Delete a Particular Node in a Tree Without Using Recursion
Custom Cascading in Spring Data MongoDB
Tính kế thừa (Inheritance) trong java
Java Program to Implement Suffix Tree
Java Program to Implement Doubly Linked List
Spring 5 Testing with @EnabledIf Annotation
Template Engines for Spring
Spring Data JPA and Null Parameters
String Processing with Apache Commons Lang 3
Disable DNS caching
Java Program to do a Breadth First Search/Traversal on a graph non-recursively
Converting String to Stream of chars
Java Program to Implement Branch and Bound Method to Perform a Combinatorial Search
Reading an HTTP Response Body as a String in Java
Sao chép các phần tử của một mảng sang mảng khác như thế nào?
Spring Security Form Login
Java Program to implement Sparse Vector
Spring MVC and the @ModelAttribute Annotation
Guide to Spring Cloud Kubernetes
Extra Login Fields with Spring Security
Comparing Two HashMaps in Java
Java Program to Find Minimum Number of Edges to Cut to make the Graph Disconnected
DistinctBy in the Java Stream API
So sánh ArrayList và Vector trong Java
Java Program to Find Hamiltonian Cycle in an UnWeighted Graph
4 tính chất của lập trình hướng đối tượng trong Java
Remove All Occurrences of a Specific Value from a List
New Features in Java 8
Iterable to Stream in Java
Sorting Query Results with Spring Data