This is a Java Program to implement Bi Directional Map. A bi-directional map is an associative data structure in which the (key, value) pairs form a one-to-one correspondence. Thus the binary relation is functional in each direction: value can also act as a key to key. A pair (a, b) thus provides a unique coupling between a and b so that b can be found when a is used as a key and a can be found when b is used as a key.
Here is the source code of the Java Program to implement Bi Directional Map. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.
/** ** Java Program to implement Bi Directional Map **/ import java.util.Scanner; import java.util.HashMap; /** class BiDrirectionalMap */ class BiDirectionalMap { private HashMap<String, String> keyVal; private HashMap<String, String> valKey; /** constructor **/ public BiDirectionalMap() { keyVal = new HashMap<String, String>(); valKey = new HashMap<String, String>(); } /** function to clear maps **/ public void clear() { keyVal.clear(); valKey.clear(); } /** function to get size of maps **/ public int size() { return keyVal.size(); } /** function to insert element **/ public void put(String key, String val) { keyVal.put(key, val); valKey.put(val, key); } /** function to get element **/ public String get(String ele) { String str = keyVal.get(ele); if (str == null) str = valKey.get(ele); return str; } /** function to remove element **/ public void remove(String key) { String val = keyVal.get(key); if (val != null) { keyVal.remove(key); valKey.remove(val); } else { val = valKey.get(key); if (val != null) { keyVal.remove(val); valKey.remove(key); } else System.out.println("\nError : Not found\n"); } } } /** Class BiDirectionalMapTest **/ public class BiDirectionalMapTest { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("Bi Directional Map Test\n"); BiDirectionalMap bdm = new BiDirectionalMap(); char ch; /** Perform Bi Directional Map operations **/ do { System.out.println("\nBi Directional Map <String, String> Operations\n"); System.out.println("1. put "); System.out.println("2. get"); System.out.println("3. remove"); System.out.println("4. clear"); System.out.println("5. size"); int choice = scan.nextInt(); switch (choice) { case 1 : System.out.println("Enter key and value"); bdm.put(scan.next(), scan.next() ); break; case 2 : System.out.println("Enter element"); String ele = scan.next(); String str = bdm.get(ele); if (str != null) System.out.println("Result : "+ str); else System.out.println("\nError : Not found\n"); break; case 3 : System.out.println("\nEnter element to be removed"); bdm.remove(scan.next() ); break; case 4 : System.out.println("\nBi Directional Map Cleared"); bdm.clear(); break; case 5 : System.out.println("\nSize = "+ bdm.size() ); break; default : System.out.println("Wrong Entry \n "); break; } System.out.println("\nDo you want to continue (Type y or n) \n"); ch = scan.next().charAt(0); } while (ch == 'Y'|| ch == 'y'); } }
Bi Directional Map Test Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 1 Enter key and value green mango Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 1 Enter key and value banana yellow Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 1 Enter key and value red apple Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element red Result : apple Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element mango Result : green Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element apple Result : red Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 5 Size = 3 Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 3 Enter element to be removed red Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element apple Error : Not found Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element red Error : Not found Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 4 Bi Directional Map Cleared Do you want to continue (Type y or n) n
Related posts:
Spring MVC + Thymeleaf 3.0: New Features
A Guide To UDP In Java
Guide to Escaping Characters in Java RegExps
Java Program to Represent Graph Using Incidence List
Send an email with an attachment
New Features in Java 10
Guide to WeakHashMap in Java
Sending Emails with Java
Guide to PriorityBlockingQueue in Java
Hướng dẫn Java Design Pattern – Interpreter
Java Scanner hasNext() vs. hasNextLine()
Java Program to Implement Stack using Two Queues
Hướng dẫn sử dụng Java Reflection
Java Program to Implement Dijkstra’s Algorithm using Queue
Spring 5 and Servlet 4 – The PushBuilder
Spring Boot - CORS Support
Java Program to Implement Hash Tables with Linear Probing
Spring Security Remember Me
Java Program to Implement Meldable Heap
Java Program to Find All Pairs Shortest Path
Dockerizing a Spring Boot Application
Java Program to Delete a Particular Node in a Tree Without Using Recursion
Java Program to Emulate N Dice Roller
Java Program to Implement Hash Trie
Spring Data Java 8 Support
Java Program to Implement Hash Tables Chaining with Doubly Linked Lists
Practical Java Examples of the Big O Notation
Java Program to Implement Range Tree
Java Program to Implement a Binary Search Tree using Linked Lists
Intro to the Jackson ObjectMapper
Guide to UUID in Java
Java Program to Construct an Expression Tree for an Infix Expression