This is a Java Program to implement Bi Directional Map. A bi-directional map is an associative data structure in which the (key, value) pairs form a one-to-one correspondence. Thus the binary relation is functional in each direction: value can also act as a key to key. A pair (a, b) thus provides a unique coupling between a and b so that b can be found when a is used as a key and a can be found when b is used as a key.
Here is the source code of the Java Program to implement Bi Directional Map. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.
/**
** Java Program to implement Bi Directional Map
**/
import java.util.Scanner;
import java.util.HashMap;
/** class BiDrirectionalMap */
class BiDirectionalMap
{
private HashMap<String, String> keyVal;
private HashMap<String, String> valKey;
/** constructor **/
public BiDirectionalMap()
{
keyVal = new HashMap<String, String>();
valKey = new HashMap<String, String>();
}
/** function to clear maps **/
public void clear()
{
keyVal.clear();
valKey.clear();
}
/** function to get size of maps **/
public int size()
{
return keyVal.size();
}
/** function to insert element **/
public void put(String key, String val)
{
keyVal.put(key, val);
valKey.put(val, key);
}
/** function to get element **/
public String get(String ele)
{
String str = keyVal.get(ele);
if (str == null)
str = valKey.get(ele);
return str;
}
/** function to remove element **/
public void remove(String key)
{
String val = keyVal.get(key);
if (val != null)
{
keyVal.remove(key);
valKey.remove(val);
}
else
{
val = valKey.get(key);
if (val != null)
{
keyVal.remove(val);
valKey.remove(key);
}
else
System.out.println("\nError : Not found\n");
}
}
}
/** Class BiDirectionalMapTest **/
public class BiDirectionalMapTest
{
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
System.out.println("Bi Directional Map Test\n");
BiDirectionalMap bdm = new BiDirectionalMap();
char ch;
/** Perform Bi Directional Map operations **/
do
{
System.out.println("\nBi Directional Map <String, String> Operations\n");
System.out.println("1. put ");
System.out.println("2. get");
System.out.println("3. remove");
System.out.println("4. clear");
System.out.println("5. size");
int choice = scan.nextInt();
switch (choice)
{
case 1 :
System.out.println("Enter key and value");
bdm.put(scan.next(), scan.next() );
break;
case 2 :
System.out.println("Enter element");
String ele = scan.next();
String str = bdm.get(ele);
if (str != null)
System.out.println("Result : "+ str);
else
System.out.println("\nError : Not found\n");
break;
case 3 :
System.out.println("\nEnter element to be removed");
bdm.remove(scan.next() );
break;
case 4 :
System.out.println("\nBi Directional Map Cleared");
bdm.clear();
break;
case 5 :
System.out.println("\nSize = "+ bdm.size() );
break;
default :
System.out.println("Wrong Entry \n ");
break;
}
System.out.println("\nDo you want to continue (Type y or n) \n");
ch = scan.next().charAt(0);
} while (ch == 'Y'|| ch == 'y');
}
}
Bi Directional Map Test Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 1 Enter key and value green mango Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 1 Enter key and value banana yellow Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 1 Enter key and value red apple Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element red Result : apple Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element mango Result : green Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element apple Result : red Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 5 Size = 3 Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 3 Enter element to be removed red Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element apple Error : Not found Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 2 Enter element red Error : Not found Do you want to continue (Type y or n) y Bi Directional Map <String, String> Operations 1. put 2. get 3. remove 4. clear 5. size 4 Bi Directional Map Cleared Do you want to continue (Type y or n) n
Related posts:
Java Program to Perform Deletion in a BST
Java Program to Find Path Between Two Nodes in a Graph
Getting Started with Custom Deserialization in Jackson
Java Program to Perform the Unique Factorization of a Given Number
Java Program to Implement Stein GCD Algorithm
Chuyển đổi Array sang ArrayList và ngược lại
Versioning a REST API
Converting Between an Array and a Set in Java
Spring REST API with Protocol Buffers
REST Web service: Tạo ứng dụng Java RESTful Client với Jersey Client 2.x
Returning Custom Status Codes from Spring Controllers
Extract network card address
Mảng (Array) trong Java
Java Program to Implement Sorted List
Overview of Spring Boot Dev Tools
Spring Boot Tutorial – Bootstrap a Simple Application
Comparing Long Values in Java
Java Program to Implement ArrayList API
Java Program to Find the Minimum value of Binary Search Tree
Spring WebClient Requests with Parameters
Java Program to Implement Interpolation Search Algorithm
Java – Delete a File
Java Program to Implement Randomized Binary Search Tree
Java Concurrency Interview Questions and Answers
Tips for dealing with HTTP-related problems
Java Program to Solve any Linear Equation in One Variable
Immutable Objects in Java
Case-Insensitive String Matching in Java
An Intro to Spring Cloud Contract
How to Return 404 with Spring WebFlux
Build a REST API with Spring and Java Config
Base64 encoding và decoding trong Java 8