Likes Display

Polycarp is working on the implementation of displaying likes on the Codehorses social network. The number of likes should be displayed in a format that will be easy to read by users. It was decided that for large numbers of likes the format should be like 123K (one hundred twenty-three thousand) or like 56M (fifty-six million).

The following displaying strategy has been approved:

• the number will be displayed either as an integer number from 0 to 999, or as a positive integer number of thousands (from 1K to 999K), or as a positive integer number of millions (from 1M on),
• the specified exact number of likes $n$ when displaying should be rounded to the nearest view from the case above (if rounding is ambiguous, it must be rounded up): for example, $1785$ should be rounded to 2K instead of 1K, $4500000$ should be rounded to 5M.

Help Polycarp implement this part of the functionality: for a given non-negative integer number of likes $n$, print its view in the Codehorses interface.Input

The first line contains an integer $t$ ($1 \le t \le 1000$) — the number of test cases in the input. The following are descriptions of the $t$ input test cases, one per line.

The description of each test case consists of a single line that contains a non-negative integer $n$ ($0 \le n \le 2\cdot10^9$) — the number of likes.Output

Print $t$ answers to the given test cases in the order from the input. Each printed value must have one of the following types:

• either an integer from 0 to 999 which corresponds just to the number of likes,
• or a number of thousands from 1K to 999K,
• or a number of millions from 1M to 2000M.

The answer is equal to a view which is the closest (by difference) to the given number $n$. If this rounding is ambiguous, then round answer up (to a greater value).Exampleinput

9
999
123
0
1782
31415926
1500
999999
35499710
2000000000

output

999
123
0
2K
31M
2K
1M
35M
2000M

Note

Let’s describe some test cases:

• $1782$ can be displayed either as 1K or as 2K but 2K is the nearest view;
• $1500$ have same difference with 1K and 2K so it should be rounded up;
• $999999$ should be displayed as 1M since it’s closer to it than to 999K.

Solution:

private fun readLn() = readLine()!! // string line
private fun readInt() = readLn().toInt() // single int
private fun readLong() = readLn().toLong() // single long
private fun readDouble() = readLn().toDouble() // single double
private fun readStrings() = readLn().split(" ") // list of strings
private fun readInts() = readStrings().map { it.toInt() } // list of ints
private fun readLongs() = readStrings().map { it.toLong() } // list of longs
private fun readDoubles() = readStrings().map { it.toDouble() } // list of doubles

fun main(args: Array<String>) {
var t = readInt()
for (q in 0..t-1) {
var n = readInt()
if (n < 1000) {
            println(n)
        } else {
            if (n >= 999500) {
if (n % 1000000 >= 500000) {
n = n - n % 1000000 + 1000000
} else {
n = n - n % 1000000
}
println("${n / 1000000}M")
} else {
if (n % 1000 >= 500) {
n = n - n % 1000 + 1000
} else {
n = n - n % 1000
}
println("${n / 1000}K")
}
}
}
}