In this program, you will learn to check whether a year is leap year or not. We will use nested if…else to solve this problem.
To understand this example, you should have the knowledge of the following Python programming topics:
A leap year is exactly divisible by 4 except for century years (years ending with 00). The century year is a leap year only if it is perfectly divisible by 400. For example,
2017 is not a leap year 1900 is a not leap year 2012 is a leap year 2000 is a leap year
Source Code
# Python program to check if year is a leap year or not
year = 2000
# To get year (integer input) from the user
# year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
Output
2000 is a leap year
You can change the value of year in the source code and run it again to test this program.
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