# Java Program to Find Path Between Two Nodes in a Graph

This is a java program find a path between two nodes in a graph if it exists. Path exists between two nodes if there is a connectivity between them through other nodes. A simple run of Breadth First Search will decide whether there is path between two given nodes or not.

Here is the source code of the Java Program to Find Path Between Two Nodes in a Graph. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.

//This is a sample program to find the minimum wire length between two component in a electrical circuits
import java.util.*;
class Node
{
public int label; // this node's label (parent node in path tree)
public int weight; // weight of edge to this node (distance to start)

public Node(int v, int w)
{
label = v;
weight = w;
}
}

public class ShortestPath
{
public static Scanner in; // for standard input
public static int n, m; // n = #vertices, m = #edges
public static int start, end; // start and end points for shortest path

public static void main(String[] args)
{
in = new Scanner(System.in);

// Input the graph:
System.out
.println("Enter the number of components and wires in a circuit:");
n = in.nextInt();
m = in.nextInt();

// Initialize adjacency list structure to empty lists:
for (int i = 0; i < n; i++)

// Add each edge twice, once for each endpoint:
System.out
.println("Mention the wire between components and its length:");
for (int i = 0; i < m; i++)
{
int v1 = in.nextInt();
int v2 = in.nextInt();
int w = in.nextInt();
}

// Input starting and ending vertices:
System.out
.println("Enter the start and end for which length is to be minimized: ");
start = in.nextInt();
end = in.nextInt();

// FOR DEBUGGING ONLY:
displayGraph();

// Print shortest path from start to end:
shortest();
}

public static void shortest()
{
boolean[] done = new boolean[n];
Node[] table = new Node[n];
for (int i = 0; i < n; i++)
table[i] = new Node(-1, Integer.MAX_VALUE);

table[start].weight = 0;

for (int count = 0; count < n; count++)
{
int min = Integer.MAX_VALUE;
int minNode = -1;
for (int i = 0; i < n; i++)
if (!done[i] && table[i].weight < min)
{
min = table[i].weight;
minNode = i;
}

done[minNode] = true;

ListIterator iter = graph[minNode].listIterator();
while (iter.hasNext())
{
Node nd = (Node) iter.next();
int v = nd.label;
int w = nd.weight;

if (!done[v] && table[minNode].weight + w < table[v].weight)
{
table[v].weight = table[minNode].weight + w;
table[v].label = minNode;
}
}
}
for (int i = 0; i < n; i++)
{
if (table[i].weight < Integer.MAX_VALUE)
{
System.out.print("Wire from " + i + " to " + start
+ " with length " + table[i].weight + ": ");
int next = table[i].label;
while (next >= 0)
{
System.out.print(next + " ");
next = table[next].label;
}
System.out.println();
} else
System.out.println("No wire from " + i + " to " + start);
}
}

public static void displayGraph()
{
for (int i = 0; i < n; i++)
{
System.out.print(i + ": ");
ListIterator nbrs = graph[i].listIterator(0);
while (nbrs.hasNext())
{
Node nd = (Node) nbrs.next();
System.out.print(nd.label + "(" + nd.weight + ") ");
}
System.out.println();
}
}
}


Output:

$javac ShortestPath.java$ java ShortestPath
Enter the number of components and wires in a circuit:
4 3
Mention the wire between components and its length:
0 1 2
1 3 3
1 2 2
Enter the start and end for which length is to be minimized:
0 1
0: 1(2)
1: 0(2) 3(3) 2(2)
2: 1(2)
3: 1(3)
Wire from 0 to 0 with length 0:
Wire from 1 to 0 with length 2: 0
Wire from 2 to 0 with length 4: 1 0
Wire from 3 to 0 with length 5: 1 0