Petr likes to come up with problems about randomly generated data. This time problem is about random permutation. He decided to generate a random permutation this way: he takes identity permutation of numbers from $1$ to $n$ and then $3n$ times takes a random pair of different elements and swaps them. Alex envies Petr and tries to imitate him in all kind of things. Alex has also come up with a problem about random permutation. He generates a random permutation just like Petr but swaps elements $7n+1$ times instead of $3n$ times. Because it is more random, OK?!
You somehow get a test from one of these problems and now you want to know from which one.
Input
In the first line of input there is one integer $n$ ($10^{3} \le n \le 10^{6}$).
In the second line there are $n$ distinct integers between $1$ and $n$ — the permutation of size $n$ from the test.
It is guaranteed that all tests except for sample are generated this way: First we choose $n$ — the size of the permutation. Then we randomly choose a method to generate a permutation — the one of Petr or the one of Alex. Then we generate a permutation using chosen method.
Output
If the test is generated via Petr’s method print “Petr” (without quotes). If the test is generated via Alex’s method print “Um_nik” (without quotes).
Example
input
5
2 4 5 1 3
output
Petr
Note
Please note that the sample is not a valid test (because of limitations for $n$) and is given only to illustrate input/output format. Your program still has to print correct answer to this test to get AC.
Due to randomness of input hacks in this problem are forbidden.
Solution:
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(0); int n; cin >> n; vector<int> a(n); for (int i = 0; i < n; i++) { cin >> a[i]; a[i]--; } vector<int> was(n, 0); int cyc = 0; for (int i = 0; i < n; i++) { if (was[i]) { continue; } cyc++; int p = i; while (!was[p]) { was[p] = 1; p = a[p]; } } cout << ((n - cyc) % 2 == (3 * n) % 2 ? "Petr" : "Um_nik") << '\n'; return 0; }