Given an undirected graph $G$ with $n$ nodes and $m$ edges. We are required to find in it all the connected components, i.e, several groups of vertices such that within a group each vertex can be reached from another and no path exists between different groups.
1. An algorithm for solving the problem
- To solve the problem, we can use Depth First Search or Breadth First Search.
- In fact, we will be doing a series of rounds of DFS: The first round will start from first node and all the nodes in the first connected component will be traversed (found). Then we find the first unvisited node of the remaining nodes, and run Depth First Search on it, thus finding a second connected component. And so on, until all the nodes are visited.
- The total asymptotic running time of this algorithm is $O(n + m)$ : In fact, this algorithm will not run on the same vertex twice, which means that each edge will be seen exactly two times (at one end and at the other end).
2. Implementation
int n;
vector<int> g[MAXN] ;
bool used[MAXN] ;
vector<int> comp ;
void dfs(int v) {
used[v] = true ;
comp.push_back(v);
for (size_t i = 0; i < (int) g[v].size(); ++i) {
int to = g[v][i];
if (!used[to])
dfs(to);
}
}
void find_comps() {
for (int i = 0; i < n ; ++i)
used [i] = false;
for (int i = 0; i < n ; ++i)
if (!used[i]) {
comp.clear();
dfs(i);
cout << "Component:" ;
for (size_t j = 0; j < comp.size(); ++j)
cout << ' ' << comp[j];
cout << endl ;
}
}
- The most important function that is used is
find_comps()which finds and displays connected components of the graph. - The graph is stored in adjacency list representation, i.e
g[i]contains a list of vertices that have edges from the vertexi. The constantMAXNshould be set equal to the maximum possible number of vertices in the graph. - Vector
compcontains a list of nodes in the current connected component.
3. Practice Problems
Related posts:
Addition on Segments
Ehab and Path-etic MEXs
Processing Queries
Good Subsets
Rowena Ravenclaw's Diadem
PolandBall and White-Red graph
Eugene and an array
The Art of Dealing with ATM
Lyndon factorization
Game with Powers
GCD Table
Design Tutorial: Learn from Life
Number of paths of fixed length / Shortest paths of fixed length
Extended Euclidean Algorithm
Coprime Permutation
Information Graph
Learning and Improving Algorithm through contests - Antti Laaksonen
Chicken or Fish?
Factorial modulo $p$
Suffix Tree. Ukkonen's Algorithm
Born This Way
Lingua Romana
LCM Challenge
Awesome Substrings
Network Mask
Greenhouse Effect
Colorado Potato Beetle
Minus and Minus Give Plus
Hot is Cold
Catalan Numbers
Pudding Monsters
Valid BFS?