Voting for Photos

After celebrating the midcourse the students of one of the faculties of the Berland State University decided to conduct a vote for the best photo. They published the photos in the social network and agreed on the rules to choose a winner: the photo which gets most likes wins. If multiple photoes get most likes, the winner is the photo that gets this number first.

Help guys determine the winner photo by the records of likes.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 1000) — the total likes to the published photoes.

The second line contains n positive integers a 1, a 2, …, a n (1 ≤ a i ≤ 1 000 000), where a i is the identifier of the photo which got the i-th like.

Output

Print the identifier of the photo which won the elections.

Examples

input

51 3 2 2 1

output

2

input

9100 200 300 200 100 300 300 100 200

output

300

Note

In the first test sample the photo with id 1 got two likes (first and fifth), photo with id 2 got two likes (third and fourth), and photo with id 3 got one like (second).

Thus, the winner is the photo with identifier 2, as it got:

• more likes than the photo with id 3;
• as many likes as the photo with id 1, but the photo with the identifier 2 got its second like earlier.

Solution:

#define __USE_MINGW_ANSI_STDIO 0
#include <bits/stdc++.h>

#define F first
#define S second
#define pb push_back
#define mp make_pair
#define forn(i, n) for(int i = 0 ; (i) < (n) ; ++i)
#define eprintf(...) fprintf(stderr, __VA_ARGS__),fflush(stderr)
#define sz(a) ((int)(a).size())
#define all(a) (a).begin(),a.end()
#define pw(x) (1LL<<(x))

using namespace std;

typedef long long ll;
typedef double dbl;
typedef vector<int> vi;
typedef pair<int, int> pi;

const int inf = (int)1.01e9;
const dbl eps = 1e-9;

/* --- main part --- */

#define TASK "1"

int a[1000111];

int main()
{
#ifdef home
assert(freopen(TASK".in", "r", stdin));
assert(freopen(TASK".out", "w", stdout));
#endif
int n;
cin >> n;
int be = 0;
int ans = -1;
while (n--) {
int x;
cin >> x;
a[x]++;
if (a[x] > be) {
be = a[x];
ans = x;
}
}
cout << ans << endl;

#ifdef home
eprintf("time = %d ms\n", (int)(clock() * 1000. / CLOCKS_PER_SEC));
#endif
return 0;
}