This is a java program to generate and print all the subsets using the Gray Code Order. The reflected binary code, also known as Gray code after Frank Gray, is a binary numeral system where two successive values differ in only one bit (binary digit). The gray code equivalent of a binary number is (number >> 1) ^ number, i.e. right-shift the number by one and EX-ORing with the original number.
Here is the source code of the Java Program to Generate All Subsets of a Given Set in the Gray Code Order. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.
//This is a java program to generate all subsets of given set of numbers using gray code order
import java.util.Random;
import java.util.Scanner;
public class Gray_Code_Permutation
{
public static int[] grayCode(int N)
{
int[] grayCode = new int[(int) Math.pow(2, N)];
int[] binary = new int[(int) Math.pow(2, N)];
for (int i = 0; i < Math.pow(2, N); i++)
grayCode[i] = (i >> 1) ^ i;
for (int i = 0; i < Math.pow(2, N); i++)
{
int b = 1;
binary[i] = 0;
while (grayCode[i] > 0)
{
binary[i] += (grayCode[i] % 2) * b;
grayCode[i] /= 2;
b = b * 10;
}
}
return binary;
}
public static void main(String args[])
{
Random random = new Random();
Scanner sc = new Scanner(System.in);
System.out.println("Enter the number of elements in the set: ");
int N = sc.nextInt();
int[] sequence = new int[N];
for (int i = 0; i < N; i++)
sequence[i] = Math.abs(random.nextInt(100));
System.out.println("The elements in the set : ");
for (int i = 0; i < N; i++)
System.out.print(sequence[i] + " ");
int[] mask = new int[(int) Math.pow(2, N)];
mask = grayCode(N);
System.out.println("\nThe permutations are: ");
for (int i = 0; i < Math.pow(2, N); i++)
{
System.out.print("{ ");
for (int j = 0; j < N; j++)
{
if (mask[i] % 10 == 1)
System.out.print(sequence[j] + " ");
mask[i] /= 10;
}
System.out.println("}");
}
sc.close();
}
}
Output:
$ javac Gray_Code_Permutation.java
$ java Gray_Code_Permutation
Enter the number of elements in the set:
4
The elements in the set :
36 75 15 59
The permutations are:
{ }
{ 36 }
{ 36 75 }
{ 75 }
{ 75 15 }
{ 36 75 15 }
{ 36 15 }
{ 15 }
{ 15 59 }
{ 36 15 59 }
{ 36 75 15 59 }
{ 75 15 59 }
{ 75 59 }
{ 36 75 59 }
{ 36 59 }
{ 59 }
Enter the number of elements in the set:
3
The elements in the set :
73 36 36
The permutations are:
{ }
{ 73 }
{ 73 36 }
{ 36 }
{ 36 36 }
{ 73 36 36 }
{ 73 36 }
{ 36 }
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