Deletion from a B-tree

In this tutorial, you will learn how to delete a key from a b-tree. Also, you will find working examples of deleting keys from a B-tree in C, C++, Java and Python.

Deleting an element on a B-tree consists of three main events: searching the node where the key to be deleted exists, deleting the key and balancing the tree if required.

While deleting a tree, a condition called underflow may occur. Underflow occurs when a node contains less than the minimum number of keys it should hold.

The terms to be understood before studying deletion operation are:

  1. Inorder Predecessor
    The largest key on the left child of a node is called its inorder predecessor.
  2. Inorder Successor
    The smallest key on the right child of a node is called its inorder successor.

1. Deletion Operation

Before going through the steps below, one must know these facts about a B tree of degree m.

  1. A node can have a maximum of m children. (i.e. 3)
  2. A node can contain a maximum of m - 1 keys. (i.e. 2)
  3. A node should have a minimum of ⌈m/2⌉ children. (i.e. 2)
  4. A node (except root node) should contain a minimum of ⌈m/2⌉ - 1 keys. (i.e. 1)

There are three main cases for deletion operation in a B tree.

1.1. Case I

The key to be deleted lies in the leaf. There are two cases for it.

The deletion of the key does not violate the property of the minimum number of keys a node should hold.

In the tree below, deleting 32 does not violate the above properties.

Delete a key from a B-tree

Deleting a leaf key (32) from B-tree

The deletion of the key violates the property of the minimum number of keys a node should hold. In this case, we borrow a key from its immediate neighboring sibling node in the order of left to right.

First, visit the immediate left sibling. If the left sibling node has more than a minimum number of keys, then borrow a key from this node.

Else, check to borrow from the immediate right sibling node.

In the tree below, deleting 31 results in the above condition. Let us borrow a key from the left sibling node.

Delete a key from a B-tree

Deleting a leaf key (31)If both the immediate sibling nodes already have a minimum number of keys, then merge the node with either the left sibling node or the right sibling node. This merging is done through the parent node.

Deleting 30 results in the above case.
 Delete a key from a B-tree

Delete a leaf key (30)

1.2. Case II

If the key to be deleted lies in the internal node, the following cases occur.

The internal node, which is deleted, is replaced by an inorder predecessor if the left child has more than the minimum number of keys.Deleting an internal nodeDeleting an internal node (33)

The internal node, which is deleted, is replaced by an inorder successor if the right child has more than the minimum number of keys.

If either child has exactly a minimum number of keys then, merge the left and the right children.
 Deleting an internal node

Deleting an internal node (30)After merging if the parent node has less than the minimum number of keys then, look for the siblings as in Case I.

1.3. Case III

In this case, the height of the tree shrinks. If the target key lies in an internal node, and the deletion of the key leads to a fewer number of keys in the node (i.e. less than the minimum required), then look for the inorder predecessor and the inorder successor. If both the children contain a minimum number of keys then, borrowing cannot take place. This leads to Case II(3) i.e. merging the children.

Again, look for the sibling to borrow a key. But, if the sibling also has only a minimum number of keys then, merge the node with the sibling along with the parent. Arrange the children accordingly (increasing order).

Deleting an internal node
Deleting an internal node (10)

2. Python, Java and C/C++ Examples

Source code by Python Language:

# Deleting a key on a B-tree in Python


# Btree node
class BTreeNode:
    def __init__(self, leaf=False):
        self.leaf = leaf
        self.keys = []
        self.child = []


class BTree:
    def __init__(self, t):
        self.root = BTreeNode(True)
        self.t = t

    # Insert a key
    def insert(self, k):
        root = self.root
        if len(root.keys) == (2 * self.t) - 1:
            temp = BTreeNode()
            self.root = temp
            temp.child.insert(0, root)
            self.split_child(temp, 0)
            self.insert_non_full(temp, k)
        else:
            self.insert_non_full(root, k)

    # Insert non full
    def insert_non_full(self, x, k):
        i = len(x.keys) - 1
        if x.leaf:
            x.keys.append((None, None))
            while i >= 0 and k[0] < x.keys[i][0]:
                x.keys[i + 1] = x.keys[i]
                i -= 1
            x.keys[i + 1] = k
        else:
            while i >= 0 and k[0] < x.keys[i][0]:
                i -= 1
            i += 1
            if len(x.child[i].keys) == (2 * self.t) - 1:
                self.split_child(x, i)
                if k[0] > x.keys[i][0]:
                    i += 1
            self.insert_non_full(x.child[i], k)

    # Split the child
    def split_child(self, x, i):
        t = self.t
        y = x.child[i]
        z = BTreeNode(y.leaf)
        x.child.insert(i + 1, z)
        x.keys.insert(i, y.keys[t - 1])
        z.keys = y.keys[t: (2 * t) - 1]
        y.keys = y.keys[0: t - 1]
        if not y.leaf:
            z.child = y.child[t: 2 * t]
            y.child = y.child[0: t - 1]

    # Delete a node
    def delete(self, x, k):
        t = self.t
        i = 0
        while i < len(x.keys) and k[0] > x.keys[i][0]:
            i += 1
        if x.leaf:
            if i < len(x.keys) and x.keys[i][0] == k[0]:
                x.keys.pop(i)
                return
            return

        if i < len(x.keys) and x.keys[i][0] == k[0]:
            return self.delete_internal_node(x, k, i)
        elif len(x.child[i].keys) >= t:
            self.delete(x.child[i], k)
        else:
            if i != 0 and i + 2 < len(x.child):
                if len(x.child[i - 1].keys) >= t:
                    self.delete_sibling(x, i, i - 1)
                elif len(x.child[i + 1].keys) >= t:
                    self.delete_sibling(x, i, i + 1)
                else:
                    self.delete_merge(x, i, i + 1)
            elif i == 0:
                if len(x.child[i + 1].keys) >= t:
                    self.delete_sibling(x, i, i + 1)
                else:
                    self.delete_merge(x, i, i + 1)
            elif i + 1 == len(x.child):
                if len(x.child[i - 1].keys) >= t:
                    self.delete_sibling(x, i, i - 1)
                else:
                    self.delete_merge(x, i, i - 1)
            self.delete(x.child[i], k)

    # Delete internal node
    def delete_internal_node(self, x, k, i):
        t = self.t
        if x.leaf:
            if x.keys[i][0] == k[0]:
                x.keys.pop(i)
                return
            return

        if len(x.child[i].keys) >= t:
            x.keys[i] = self.delete_predecessor(x.child[i])
            return
        elif len(x.child[i + 1].keys) >= t:
            x.keys[i] = self.delete_successor(x.child[i + 1])
            return
        else:
            self.delete_merge(x, i, i + 1)
            self.delete_internal_node(x.child[i], k, self.t - 1)

    # Delete the predecessor
    def delete_predecessor(self, x):
        if x.leaf:
            return x.pop()
        n = len(x.keys) - 1
        if len(x.child[n].keys) >= self.t:
            self.delete_sibling(x, n + 1, n)
        else:
            self.delete_merge(x, n, n + 1)
        self.delete_predecessor(x.child[n])

    # Delete the successor
    def delete_successor(self, x):
        if x.leaf:
            return x.keys.pop(0)
        if len(x.child[1].keys) >= self.t:
            self.delete_sibling(x, 0, 1)
        else:
            self.delete_merge(x, 0, 1)
        self.delete_successor(x.child[0])

    # Delete resolution
    def delete_merge(self, x, i, j):
        cnode = x.child[i]

        if j > i:
            rsnode = x.child[j]
            cnode.keys.append(x.keys[i])
            for k in range(len(rsnode.keys)):
                cnode.keys.append(rsnode.keys[k])
                if len(rsnode.child) > 0:
                    cnode.child.append(rsnode.child[k])
            if len(rsnode.child) > 0:
                cnode.child.append(rsnode.child.pop())
            new = cnode
            x.keys.pop(i)
            x.child.pop(j)
        else:
            lsnode = x.child[j]
            lsnode.keys.append(x.keys[j])
            for i in range(len(cnode.keys)):
                lsnode.keys.append(cnode.keys[i])
                if len(lsnode.child) > 0:
                    lsnode.child.append(cnode.child[i])
            if len(lsnode.child) > 0:
                lsnode.child.append(cnode.child.pop())
            new = lsnode
            x.keys.pop(j)
            x.child.pop(i)

        if x == self.root and len(x.keys) == 0:
            self.root = new

    # Delete the sibling
    def delete_sibling(self, x, i, j):
        cnode = x.child[i]
        if i < j:
            rsnode = x.child[j]
            cnode.keys.append(x.keys[i])
            x.keys[i] = rsnode.keys[0]
            if len(rsnode.child) > 0:
                cnode.child.append(rsnode.child[0])
                rsnode.child.pop(0)
            rsnode.keys.pop(0)
        else:
            lsnode = x.child[j]
            cnode.keys.insert(0, x.keys[i - 1])
            x.keys[i - 1] = lsnode.keys.pop()
            if len(lsnode.child) > 0:
                cnode.child.insert(0, lsnode.child.pop())

    # Print the tree
    def print_tree(self, x, l=0):
        print("Level ", l, " ", len(x.keys), end=":")
        for i in x.keys:
            print(i, end=" ")
        print()
        l += 1
        if len(x.child) > 0:
            for i in x.child:
                self.print_tree(i, l)



B = BTree(3)

for i in range(10):
    B.insert((i, 2 * i))

B.print_tree(B.root)

B.delete(B.root, (8,))
print("\n")
B.print_tree(B.root)

Source code by Java Language:

// Inserting a key on a B-tree in Java

import java.util.Stack;

public class BTree {

  private int T;

  public class Node {
    int n;
    int key[] = new int[2 * T - 1];
    Node child[] = new Node[2 * T];
    boolean leaf = true;

    public int Find(int k) {
      for (int i = 0; i < this.n; i++) {
        if (this.key[i] == k) {
          return i;
        }
      }
      return -1;
    };
  }

  public BTree(int t) {
    T = t;
    root = new Node();
    root.n = 0;
    root.leaf = true;
  }

  private Node root;

  // Search the key
  private Node Search(Node x, int key) {
    int i = 0;
    if (x == null)
      return x;
    for (i = 0; i < x.n; i++) {
      if (key < x.key[i]) {
        break;
      }
      if (key == x.key[i]) {
        return x;
      }
    }
    if (x.leaf) {
      return null;
    } else {
      return Search(x.child[i], key);
    }
  }

  // Split function
  private void Split(Node x, int pos, Node y) {
    Node z = new Node();
    z.leaf = y.leaf;
    z.n = T - 1;
    for (int j = 0; j < T - 1; j++) {
      z.key[j] = y.key[j + T];
    }
    if (!y.leaf) {
      for (int j = 0; j < T; j++) {
        z.child[j] = y.child[j + T];
      }
    }
    y.n = T - 1;
    for (int j = x.n; j >= pos + 1; j--) {
      x.child[j + 1] = x.child[j];
    }
    x.child[pos + 1] = z;

    for (int j = x.n - 1; j >= pos; j--) {
      x.key[j + 1] = x.key[j];
    }
    x.key[pos] = y.key[T - 1];
    x.n = x.n + 1;
  }

  // Insert the key
  public void Insert(final int key) {
    Node r = root;
    if (r.n == 2 * T - 1) {
      Node s = new Node();
      root = s;
      s.leaf = false;
      s.n = 0;
      s.child[0] = r;
      Split(s, 0, r);
      _Insert(s, key);
    } else {
      _Insert(r, key);
    }
  }

  // Insert the node
  final private void _Insert(Node x, int k) {

    if (x.leaf) {
      int i = 0;
      for (i = x.n - 1; i >= 0 && k < x.key[i]; i--) {
        x.key[i + 1] = x.key[i];
      }
      x.key[i + 1] = k;
      x.n = x.n + 1;
    } else {
      int i = 0;
      for (i = x.n - 1; i >= 0 && k < x.key[i]; i--) {
      }
      ;
      i++;
      Node tmp = x.child[i];
      if (tmp.n == 2 * T - 1) {
        Split(x, i, tmp);
        if (k > x.key[i]) {
          i++;
        }
      }
      _Insert(x.child[i], k);
    }

  }

  public void Show() {
    Show(root);
  }

  private void Remove(Node x, int key) {
    int pos = x.Find(key);
    if (pos != -1) {
      if (x.leaf) {
        int i = 0;
        for (i = 0; i < x.n && x.key[i] != key; i++) {
        }
        ;
        for (; i < x.n; i++) {
          if (i != 2 * T - 2) {
            x.key[i] = x.key[i + 1];
          }
        }
        x.n--;
        return;
      }
      if (!x.leaf) {

        Node pred = x.child[pos];
        int predKey = 0;
        if (pred.n >= T) {
          for (;;) {
            if (pred.leaf) {
              System.out.println(pred.n);
              predKey = pred.key[pred.n - 1];
              break;
            } else {
              pred = pred.child[pred.n];
            }
          }
          Remove(pred, predKey);
          x.key[pos] = predKey;
          return;
        }

        Node nextNode = x.child[pos + 1];
        if (nextNode.n >= T) {
          int nextKey = nextNode.key[0];
          if (!nextNode.leaf) {
            nextNode = nextNode.child[0];
            for (;;) {
              if (nextNode.leaf) {
                nextKey = nextNode.key[nextNode.n - 1];
                break;
              } else {
                nextNode = nextNode.child[nextNode.n];
              }
            }
          }
          Remove(nextNode, nextKey);
          x.key[pos] = nextKey;
          return;
        }

        int temp = pred.n + 1;
        pred.key[pred.n++] = x.key[pos];
        for (int i = 0, j = pred.n; i < nextNode.n; i++) {
          pred.key[j++] = nextNode.key[i];
          pred.n++;
        }
        for (int i = 0; i < nextNode.n + 1; i++) {
          pred.child[temp++] = nextNode.child[i];
        }

        x.child[pos] = pred;
        for (int i = pos; i < x.n; i++) {
          if (i != 2 * T - 2) {
            x.key[i] = x.key[i + 1];
          }
        }
        for (int i = pos + 1; i < x.n + 1; i++) {
          if (i != 2 * T - 1) {
            x.child[i] = x.child[i + 1];
          }
        }
        x.n--;
        if (x.n == 0) {
          if (x == root) {
            root = x.child[0];
          }
          x = x.child[0];
        }
        Remove(pred, key);
        return;
      }
    } else {
      for (pos = 0; pos < x.n; pos++) {
        if (x.key[pos] > key) {
          break;
        }
      }
      Node tmp = x.child[pos];
      if (tmp.n >= T) {
        Remove(tmp, key);
        return;
      }
      if (true) {
        Node nb = null;
        int devider = -1;

        if (pos != x.n && x.child[pos + 1].n >= T) {
          devider = x.key[pos];
          nb = x.child[pos + 1];
          x.key[pos] = nb.key[0];
          tmp.key[tmp.n++] = devider;
          tmp.child[tmp.n] = nb.child[0];
          for (int i = 1; i < nb.n; i++) {
            nb.key[i - 1] = nb.key[i];
          }
          for (int i = 1; i <= nb.n; i++) {
            nb.child[i - 1] = nb.child[i];
          }
          nb.n--;
          Remove(tmp, key);
          return;
        } else if (pos != 0 && x.child[pos - 1].n >= T) {

          devider = x.key[pos - 1];
          nb = x.child[pos - 1];
          x.key[pos - 1] = nb.key[nb.n - 1];
          Node child = nb.child[nb.n];
          nb.n--;

          for (int i = tmp.n; i > 0; i--) {
            tmp.key[i] = tmp.key[i - 1];
          }
          tmp.key[0] = devider;
          for (int i = tmp.n + 1; i > 0; i--) {
            tmp.child[i] = tmp.child[i - 1];
          }
          tmp.child[0] = child;
          tmp.n++;
          Remove(tmp, key);
          return;
        } else {
          Node lt = null;
          Node rt = null;
          boolean last = false;
          if (pos != x.n) {
            devider = x.key[pos];
            lt = x.child[pos];
            rt = x.child[pos + 1];
          } else {
            devider = x.key[pos - 1];
            rt = x.child[pos];
            lt = x.child[pos - 1];
            last = true;
            pos--;
          }
          for (int i = pos; i < x.n - 1; i++) {
            x.key[i] = x.key[i + 1];
          }
          for (int i = pos + 1; i < x.n; i++) {
            x.child[i] = x.child[i + 1];
          }
          x.n--;
          lt.key[lt.n++] = devider;

          for (int i = 0, j = lt.n; i < rt.n + 1; i++, j++) {
            if (i < rt.n) {
              lt.key[j] = rt.key[i];
            }
            lt.child[j] = rt.child[i];
          }
          lt.n += rt.n;
          if (x.n == 0) {
            if (x == root) {
              root = x.child[0];
            }
            x = x.child[0];
          }
          Remove(lt, key);
          return;
        }
      }
    }
  }

  public void Remove(int key) {
    Node x = Search(root, key);
    if (x == null) {
      return;
    }
    Remove(root, key);
  }

  public void Task(int a, int b) {
    Stack<Integer> st = new Stack<>();
    FindKeys(a, b, root, st);
    while (st.isEmpty() == false) {
      this.Remove(root, st.pop());
    }
  }

  private void FindKeys(int a, int b, Node x, Stack<Integer> st) {
    int i = 0;
    for (i = 0; i < x.n && x.key[i] < b; i++) {
      if (x.key[i] > a) {
        st.push(x.key[i]);
      }
    }
    if (!x.leaf) {
      for (int j = 0; j < i + 1; j++) {
        FindKeys(a, b, x.child[j], st);
      }
    }
  }

  public boolean Contain(int k) {
    if (this.Search(root, k) != null) {
      return true;
    } else {
      return false;
    }
  }

  // Show the node
  private void Show(Node x) {
    assert (x == null);
    for (int i = 0; i < x.n; i++) {
      System.out.print(x.key[i] + " ");
    }
    if (!x.leaf) {
      for (int i = 0; i < x.n + 1; i++) {
        Show(x.child[i]);
      }
    }
  }

  public static void main(String[] args) {
    BTree b = new BTree(3);
    b.Insert(8);
    b.Insert(9);
    b.Insert(10);
    b.Insert(11);
    b.Insert(15);
    b.Insert(20);
    b.Insert(17);

    b.Show();

    b.Remove(10);
    System.out.println();
    b.Show();
  }
}

Source code by C Language:

// Deleting a key from a B-tree in C

#include <stdio.h>
#include <stdlib.h>

#define MAX 3
#define MIN 2

struct BTreeNode {
  int item[MAX + 1], count;
  struct BTreeNode *linker[MAX + 1];
};

struct BTreeNode *root;

// Node creation
struct BTreeNode *createNode(int item, struct BTreeNode *child) {
  struct BTreeNode *newNode;
  newNode = (struct BTreeNode *)malloc(sizeof(struct BTreeNode));
  newNode->item[1] = item;
  newNode->count = 1;
  newNode->linker[0] = root;
  newNode->linker[1] = child;
  return newNode;
}

// Add value to the node
void addValToNode(int item, int pos, struct BTreeNode *node,
          struct BTreeNode *child) {
  int j = node->count;
  while (j > pos) {
    node->item[j + 1] = node->item[j];
    node->linker[j + 1] = node->linker[j];
    j--;
  }
  node->item[j + 1] = item;
  node->linker[j + 1] = child;
  node->count++;
}

// Split the node
void splitNode(int item, int *pval, int pos, struct BTreeNode *node,
         struct BTreeNode *child, struct BTreeNode **newNode) {
  int median, j;

  if (pos > MIN)
    median = MIN + 1;
  else
    median = MIN;

  *newNode = (struct BTreeNode *)malloc(sizeof(struct BTreeNode));
  j = median + 1;
  while (j <= MAX) {
    (*newNode)->item[j - median] = node->item[j];
    (*newNode)->linker[j - median] = node->linker[j];
    j++;
  }
  node->count = median;
  (*newNode)->count = MAX - median;

  if (pos <= MIN) {
    addValToNode(item, pos, node, child);
  } else {
    addValToNode(item, pos - median, *newNode, child);
  }
  *pval = node->item[node->count];
  (*newNode)->linker[0] = node->linker[node->count];
  node->count--;
}

// Set the value in the node
int setValueInNode(int item, int *pval,
           struct BTreeNode *node, struct BTreeNode **child) {
  int pos;
  if (!node) {
    *pval = item;
    *child = NULL;
    return 1;
  }

  if (item < node->item[1]) {
    pos = 0;
  } else {
    for (pos = node->count;
       (item < node->item[pos] && pos > 1); pos--)
      ;
    if (item == node->item[pos]) {
      printf("Duplicates not allowed\n");
      return 0;
    }
  }
  if (setValueInNode(item, pval, node->linker[pos], child)) {
    if (node->count < MAX) {
      addValToNode(*pval, pos, node, *child);
    } else {
      splitNode(*pval, pval, pos, node, *child, child);
      return 1;
    }
  }
  return 0;
}

// Insertion operation
void insertion(int item) {
  int flag, i;
  struct BTreeNode *child;

  flag = setValueInNode(item, &i, root, &child);
  if (flag)
    root = createNode(i, child);
}

// Copy the successor
void copySuccessor(struct BTreeNode *myNode, int pos) {
  struct BTreeNode *dummy;
  dummy = myNode->linker[pos];

  for (; dummy->linker[0] != NULL;)
    dummy = dummy->linker[0];
  myNode->item[pos] = dummy->item[1];
}

// Remove the value
void removeVal(struct BTreeNode *myNode, int pos) {
  int i = pos + 1;
  while (i <= myNode->count) {
    myNode->item[i - 1] = myNode->item[i];
    myNode->linker[i - 1] = myNode->linker[i];
    i++;
  }
  myNode->count--;
}

// Do right shift
void rightShift(struct BTreeNode *myNode, int pos) {
  struct BTreeNode *x = myNode->linker[pos];
  int j = x->count;

  while (j > 0) {
    x->item[j + 1] = x->item[j];
    x->linker[j + 1] = x->linker[j];
  }
  x->item[1] = myNode->item[pos];
  x->linker[1] = x->linker[0];
  x->count++;

  x = myNode->linker[pos - 1];
  myNode->item[pos] = x->item[x->count];
  myNode->linker[pos] = x->linker[x->count];
  x->count--;
  return;
}

// Do left shift
void leftShift(struct BTreeNode *myNode, int pos) {
  int j = 1;
  struct BTreeNode *x = myNode->linker[pos - 1];

  x->count++;
  x->item[x->count] = myNode->item[pos];
  x->linker[x->count] = myNode->linker[pos]->linker[0];

  x = myNode->linker[pos];
  myNode->item[pos] = x->item[1];
  x->linker[0] = x->linker[1];
  x->count--;

  while (j <= x->count) {
    x->item[j] = x->item[j + 1];
    x->linker[j] = x->linker[j + 1];
    j++;
  }
  return;
}

// Merge the nodes
void mergeNodes(struct BTreeNode *myNode, int pos) {
  int j = 1;
  struct BTreeNode *x1 = myNode->linker[pos], *x2 = myNode->linker[pos - 1];

  x2->count++;
  x2->item[x2->count] = myNode->item[pos];
  x2->linker[x2->count] = myNode->linker[0];

  while (j <= x1->count) {
    x2->count++;
    x2->item[x2->count] = x1->item[j];
    x2->linker[x2->count] = x1->linker[j];
    j++;
  }

  j = pos;
  while (j < myNode->count) {
    myNode->item[j] = myNode->item[j + 1];
    myNode->linker[j] = myNode->linker[j + 1];
    j++;
  }
  myNode->count--;
  free(x1);
}

// Adjust the node
void adjustNode(struct BTreeNode *myNode, int pos) {
  if (!pos) {
    if (myNode->linker[1]->count > MIN) {
      leftShift(myNode, 1);
    } else {
      mergeNodes(myNode, 1);
    }
  } else {
    if (myNode->count != pos) {
      if (myNode->linker[pos - 1]->count > MIN) {
        rightShift(myNode, pos);
      } else {
        if (myNode->linker[pos + 1]->count > MIN) {
          leftShift(myNode, pos + 1);
        } else {
          mergeNodes(myNode, pos);
        }
      }
    } else {
      if (myNode->linker[pos - 1]->count > MIN)
        rightShift(myNode, pos);
      else
        mergeNodes(myNode, pos);
    }
  }
}

// Delete a value from the node
int delValFromNode(int item, struct BTreeNode *myNode) {
  int pos, flag = 0;
  if (myNode) {
    if (item < myNode->item[1]) {
      pos = 0;
      flag = 0;
    } else {
      for (pos = myNode->count; (item < myNode->item[pos] && pos > 1); pos--)
        ;
      if (item == myNode->item[pos]) {
        flag = 1;
      } else {
        flag = 0;
      }
    }
    if (flag) {
      if (myNode->linker[pos - 1]) {
        copySuccessor(myNode, pos);
        flag = delValFromNode(myNode->item[pos], myNode->linker[pos]);
        if (flag == 0) {
          printf("Given data is not present in B-Tree\n");
        }
      } else {
        removeVal(myNode, pos);
      }
    } else {
      flag = delValFromNode(item, myNode->linker[pos]);
    }
    if (myNode->linker[pos]) {
      if (myNode->linker[pos]->count < MIN)
        adjustNode(myNode, pos);
    }
  }
  return flag;
}

// Delete operaiton
void delete (int item, struct BTreeNode *myNode) {
  struct BTreeNode *tmp;
  if (!delValFromNode(item, myNode)) {
    printf("Not present\n");
    return;
  } else {
    if (myNode->count == 0) {
      tmp = myNode;
      myNode = myNode->linker[0];
      free(tmp);
    }
  }
  root = myNode;
  return;
}

void searching(int item, int *pos, struct BTreeNode *myNode) {
  if (!myNode) {
    return;
  }

  if (item < myNode->item[1]) {
    *pos = 0;
  } else {
    for (*pos = myNode->count;
       (item < myNode->item[*pos] && *pos > 1); (*pos)--)
      ;
    if (item == myNode->item[*pos]) {
      printf("%d present in B-tree", item);
      return;
    }
  }
  searching(item, pos, myNode->linker[*pos]);
  return;
}

void traversal(struct BTreeNode *myNode) {
  int i;
  if (myNode) {
    for (i = 0; i < myNode->count; i++) {
      traversal(myNode->linker[i]);
      printf("%d ", myNode->item[i + 1]);
    }
    traversal(myNode->linker[i]);
  }
}

int main() {
  int item, ch;

  insertion(8);
  insertion(9);
  insertion(10);
  insertion(11);
  insertion(15);
  insertion(16);
  insertion(17);
  insertion(18);
  insertion(20);
  insertion(23);

  traversal(root);

  delete (20, root);
  printf("\n");
  traversal(root);
}

Source code by C++ Language:

// Deleting a key from a B-tree in C++

#include <iostream>
using namespace std;

class BTreeNode {
  int *keys;
  int t;
  BTreeNode **C;
  int n;
  bool leaf;

   public:
  BTreeNode(int _t, bool _leaf);

  void traverse();

  int findKey(int k);
  void insertNonFull(int k);
  void splitChild(int i, BTreeNode *y);
  void deletion(int k);
  void removeFromLeaf(int idx);
  void removeFromNonLeaf(int idx);
  int getPredecessor(int idx);
  int getSuccessor(int idx);
  void fill(int idx);
  void borrowFromPrev(int idx);
  void borrowFromNext(int idx);
  void merge(int idx);
  friend class BTree;
};

class BTree {
  BTreeNode *root;
  int t;

   public:
  BTree(int _t) {
    root = NULL;
    t = _t;
  }

  void traverse() {
    if (root != NULL)
      root->traverse();
  }

  void insertion(int k);

  void deletion(int k);
};

// B tree node
BTreeNode::BTreeNode(int t1, bool leaf1) {
  t = t1;
  leaf = leaf1;

  keys = new int[2 * t - 1];
  C = new BTreeNode *[2 * t];

  n = 0;
}

// Find the key
int BTreeNode::findKey(int k) {
  int idx = 0;
  while (idx < n && keys[idx] < k)
    ++idx;
  return idx;
}

// Deletion operation
void BTreeNode::deletion(int k) {
  int idx = findKey(k);

  if (idx < n && keys[idx] == k) {
    if (leaf)
      removeFromLeaf(idx);
    else
      removeFromNonLeaf(idx);
  } else {
    if (leaf) {
      cout << "The key " << k << " is does not exist in the tree\n";
      return;
    }

    bool flag = ((idx == n) ? true : false);

    if (C[idx]->n < t)
      fill(idx);

    if (flag && idx > n)
      C[idx - 1]->deletion(k);
    else
      C[idx]->deletion(k);
  }
  return;
}

// Remove from the leaf
void BTreeNode::removeFromLeaf(int idx) {
  for (int i = idx + 1; i < n; ++i)
    keys[i - 1] = keys[i];

  n--;

  return;
}

// Delete from non leaf node
void BTreeNode::removeFromNonLeaf(int idx) {
  int k = keys[idx];

  if (C[idx]->n >= t) {
    int pred = getPredecessor(idx);
    keys[idx] = pred;
    C[idx]->deletion(pred);
  }

  else if (C[idx + 1]->n >= t) {
    int succ = getSuccessor(idx);
    keys[idx] = succ;
    C[idx + 1]->deletion(succ);
  }

  else {
    merge(idx);
    C[idx]->deletion(k);
  }
  return;
}

int BTreeNode::getPredecessor(int idx) {
  BTreeNode *cur = C[idx];
  while (!cur->leaf)
    cur = cur->C[cur->n];

  return cur->keys[cur->n - 1];
}

int BTreeNode::getSuccessor(int idx) {
  BTreeNode *cur = C[idx + 1];
  while (!cur->leaf)
    cur = cur->C[0];

  return cur->keys[0];
}

void BTreeNode::fill(int idx) {
  if (idx != 0 && C[idx - 1]->n >= t)
    borrowFromPrev(idx);

  else if (idx != n && C[idx + 1]->n >= t)
    borrowFromNext(idx);

  else {
    if (idx != n)
      merge(idx);
    else
      merge(idx - 1);
  }
  return;
}

// Borrow from previous
void BTreeNode::borrowFromPrev(int idx) {
  BTreeNode *child = C[idx];
  BTreeNode *sibling = C[idx - 1];

  for (int i = child->n - 1; i >= 0; --i)
    child->keys[i + 1] = child->keys[i];

  if (!child->leaf) {
    for (int i = child->n; i >= 0; --i)
      child->C[i + 1] = child->C[i];
  }

  child->keys[0] = keys[idx - 1];

  if (!child->leaf)
    child->C[0] = sibling->C[sibling->n];

  keys[idx - 1] = sibling->keys[sibling->n - 1];

  child->n += 1;
  sibling->n -= 1;

  return;
}

// Borrow from the next
void BTreeNode::borrowFromNext(int idx) {
  BTreeNode *child = C[idx];
  BTreeNode *sibling = C[idx + 1];

  child->keys[(child->n)] = keys[idx];

  if (!(child->leaf))
    child->C[(child->n) + 1] = sibling->C[0];

  keys[idx] = sibling->keys[0];

  for (int i = 1; i < sibling->n; ++i)
    sibling->keys[i - 1] = sibling->keys[i];

  if (!sibling->leaf) {
    for (int i = 1; i <= sibling->n; ++i)
      sibling->C[i - 1] = sibling->C[i];
  }

  child->n += 1;
  sibling->n -= 1;

  return;
}

// Merge
void BTreeNode::merge(int idx) {
  BTreeNode *child = C[idx];
  BTreeNode *sibling = C[idx + 1];

  child->keys[t - 1] = keys[idx];

  for (int i = 0; i < sibling->n; ++i)
    child->keys[i + t] = sibling->keys[i];

  if (!child->leaf) {
    for (int i = 0; i <= sibling->n; ++i)
      child->C[i + t] = sibling->C[i];
  }

  for (int i = idx + 1; i < n; ++i)
    keys[i - 1] = keys[i];

  for (int i = idx + 2; i <= n; ++i)
    C[i - 1] = C[i];

  child->n += sibling->n + 1;
  n--;

  delete (sibling);
  return;
}

// Insertion operation
void BTree::insertion(int k) {
  if (root == NULL) {
    root = new BTreeNode(t, true);
    root->keys[0] = k;
    root->n = 1;
  } else {
    if (root->n == 2 * t - 1) {
      BTreeNode *s = new BTreeNode(t, false);

      s->C[0] = root;

      s->splitChild(0, root);

      int i = 0;
      if (s->keys[0] < k)
        i++;
      s->C[i]->insertNonFull(k);

      root = s;
    } else
      root->insertNonFull(k);
  }
}

// Insertion non full
void BTreeNode::insertNonFull(int k) {
  int i = n - 1;

  if (leaf == true) {
    while (i >= 0 && keys[i] > k) {
      keys[i + 1] = keys[i];
      i--;
    }

    keys[i + 1] = k;
    n = n + 1;
  } else {
    while (i >= 0 && keys[i] > k)
      i--;

    if (C[i + 1]->n == 2 * t - 1) {
      splitChild(i + 1, C[i + 1]);

      if (keys[i + 1] < k)
        i++;
    }
    C[i + 1]->insertNonFull(k);
  }
}

// Split child
void BTreeNode::splitChild(int i, BTreeNode *y) {
  BTreeNode *z = new BTreeNode(y->t, y->leaf);
  z->n = t - 1;

  for (int j = 0; j < t - 1; j++)
    z->keys[j] = y->keys[j + t];

  if (y->leaf == false) {
    for (int j = 0; j < t; j++)
      z->C[j] = y->C[j + t];
  }

  y->n = t - 1;

  for (int j = n; j >= i + 1; j--)
    C[j + 1] = C[j];

  C[i + 1] = z;

  for (int j = n - 1; j >= i; j--)
    keys[j + 1] = keys[j];

  keys[i] = y->keys[t - 1];

  n = n + 1;
}

// Traverse
void BTreeNode::traverse() {
  int i;
  for (i = 0; i < n; i++) {
    if (leaf == false)
      C[i]->traverse();
    cout << " " << keys[i];
  }

  if (leaf == false)
    C[i]->traverse();
}

// Delete Operation
void BTree::deletion(int k) {
  if (!root) {
    cout << "The tree is empty\n";
    return;
  }

  root->deletion(k);

  if (root->n == 0) {
    BTreeNode *tmp = root;
    if (root->leaf)
      root = NULL;
    else
      root = root->C[0];

    delete tmp;
  }
  return;
}

int main() {
  BTree t(3);
  t.insertion(8);
  t.insertion(9);
  t.insertion(10);
  t.insertion(11);
  t.insertion(15);
  t.insertion(16);
  t.insertion(17);
  t.insertion(18);
  t.insertion(20);
  t.insertion(23);

  cout << "The B-tree is: ";
  t.traverse();

  t.deletion(20);

  cout << "\nThe B-tree is: ";
  t.traverse();
}

3. Deletion Complexity

Best case Time complexity: Θ(log n)

Average case Space complexity: Θ(n)

Worst case Space complexity: Θ(n)